hi pple,
look at the codes.

printf("%ld",1000*1000);

this gives an answer '0' zero.
but the range of longdouble is far more than the answer.
why it dosent gives a write answer.
thankx.

Why don't you set the value of a long double variable to 1000*1000 and then printf that instead. [addsig]

Maybe because %ld is long int, not long double, eh?

[Lesson: Read the manual. ]

i know that if i do long a;
a=1000*1000;
printf("%ld",a);
i will get the answer but wats wrong with the code i wrote.

You don't run into this problem here, but you need to be aware that as 1000 is an int, the expression 1000 * 1000 will be evaluated with integer multiplication. Therefore, the integer limits apply, so if you did 1000 * 1000 * 1000 * 1000, you would get problems.

I think that's right.