I just started learning C today! I'm so happy! I was making a calculator and I don't know how to make exponents. I have just the code, but I don't know how to tell the computer that its an exponent. Here's the code I have so far (It just asks for two numbers. First one (a) is supposed to be the number, second is the exponent, which is b. The answer is c.).

Code:
#include <stdio.h>

int main()
{
int a, b, c;
printf("Enter the number:");
scanf("%d", &a);
printf("Enter the exponent:");
scanf("%d", &b);
c = a ** b; /* This is the exponent line. I don't know what to do here in order to make an exponent. */
printf("%d with an exponent of %d = %dn", a, b, c);
return 0;
}


It'd be good if you could tell me how to make exponents, thanks!

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[ This Message was edited by: Jason on 2002-09-08 14:50 ]

c = a ** b; .. i think that this line is not right, what is ** ? i think you should try ---->--> c = a ^ b;
That should work.

No, no. Were you joking, sg?

Something like this is more likely to work:

//At the beginning of your program:
#include <math.h>

...
...
...

c = pow (a, b);

...
...


[ This Message was edited by: seunosewa on 2002-09-08 18:09 ]

Thanks, seunosewa! It worked! I owe you one . [addsig]

sorry about that , but Jason here is another implementation of the exponent function without using the math.h header file.


#include


int a, b, c;

int pow(int,int);

int main()
{

printf("Enter the number:");
scanf("%d", &a);
printf("Enter the exponent:");
scanf("%d", &b);
c = pow(a,b); /* this calls the function pow, which i have created not the one present in the math.h header file */
printf("%d with an exponent of %d = %d", a, b, c);
return 0;
}


int pow(int a,int b)
{
int reslt = 1,count;


for(count = a; b -->= 1 ; b--)

reslt = (reslt * a);


return (reslt);

}

i hope you like this example better, do copy it and play around with the codei have pasted ....

Well, I would say that its better to include the math.h header file under normal conditions ... and I can't think of any exception right now (hint, hint)

Couldn't you just do something like:

int a=input number;
int b=exponent;
int x;
int answer;
answer=a;
for(x=0; x<b; x++){
answer*=answer;
}
if(b==0){
answer=1;
}
if(b==1){
answer=a;
}
printf("answer:%i", answer);

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Huh? Stop confusing me.

[ This Message was edited by: AntiHalcyon on 2002-09-15 08:18 ]

Obviously that won't work for exponents that aren't nonnegative integers. Also, for exponents that are non-tiny but small enough that the result of exponentiation will fit in an integer, the floating point exp might be faster, since it will use fancy tables 'n' stuff.

True... Well I was wrong as usual. [addsig]